CalcuForge
Real Estate & Civil

Brick, Mortar & Masonry Block Estimator

Enter wall dimensions, deduct door and window openings, and get the brick count plus cement and sand needed for the mortar.

230mm ≈ one full brick length; 115mm ≈ half brick.

Bricks required
1,691pieces
Cement
4.3bags (50kg)
Sand
1,421kg
Full material breakdown
QuantityValue
Net wall volume (openings deducted)3.381 m³
Bricks required1691 pieces
Mortar volume0.779 m³
Cement4.3 bags · 213 kg
Sand0.888 m³ · 1,421 kg
Formula

How material quantities are derived

Bricks = Net wall volume ÷ (brick + joint volume)
Mortar = Net wall volume − (Bricks × brick volume)
Net wall volumeLength × height × thickness, minus opening area × thickness
Brick + joint volume(L+j) × (W+j) × (H+j), where j is the mortar joint thickness
Mortar splitDry mortar volume divided across the cement:sand ratio
Worked example

A 6m × 3m wall, 230mm thick, with 4m² of openings

Gross wall volume is 6 × 3 × 0.23 ≈ 4.14 m³. Subtracting 4 m² of openings (× 0.23m thickness ≈ 0.92 m³) and adding 5% wastage gives a net volume of about 3.38 m³. Using modular bricks with a 10mm joint, that works out to roughly 1,660 bricks, with the leftover mortar volume split across a 1:6 cement:sand ratio to about 6.4 bags of cement and 490 kg of sand.

MaterialQuantity
Bricks≈ 1,660 pieces
Cement≈ 6.4 bags
Sand≈ 490 kg
FAQ

Common questions

It divides the net wall volume (after deducting openings) by the volume of a single brick plus the mortar joint that surrounds it on the length, width, and height sides. That "brick + mortar" volume is larger than the brick alone, since the mortar joint takes up space too — dividing by it directly gives the number of bricks that fit, and the mortar volume is calculated separately as the leftover space between bricks.

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